Your answer is correct...but you are missing last step.
There are 10 Boys & 6 girls in class. No other combination is possible.
So, 2 boys shorter than shortest girl &
2 girls taller than tallest boys

this leaves 12 students = 10 intermediaries + 1 tallest boy + 1 shortest girl.

Question asks the no. of intermediaries

Super hard. any other explanation.

NOTE: I'm probably over explaining things here, but I want the solution to be absolutely clear.



GIVEN: There are 16 students and 1/5 of them are boys.
This means the number of boys must be a multiple of 5.
There are 3 possible cases:
i) 5 boys and 11 girls
ii) 10 boys and 6 girls
iii) 15 boys and 1 girl

GIVEN: There are 16 students and 1/3 of them are girls.
This means the number of girls must be a multiple of 3.
When we check the three possible cases above, we see that only one case (case ii) is such that the number of girls is divisible by 3.

So we now know that there are 10 boys and 6 girls

Let A, B, C, D, E, F represent the heights of the 6 girls arranged in ASCENDING order
Let Q, R, S, T, U, V, W, X, Y, Z represent the heights of the 10 boys arranged in ASCENDING order

1/5 of the boys are shorter than the shortest girl in the class
1/5 of 10 = 2
So, 2 boys are shorter than the shortest girl in the class
We have: Q, R, A [ these 3 heights must be arranged in ascending order]


1/3 of the girls are taller than the tallest boy in the class
1/3 of 2 = 2
So, 2 girls are taller than the tallest boy in the class
We have: Z, E, F [ these 3 heights must be arranged in ascending order]

NOTE: The remaining students must lie BETWEEN A and Z, however there is no way to determine the relationships between each boy and each girl within this range.

So one possible configuration is as follows: Q, R, A, S, T, U, V, W, X, Y, B, C, D, Z, E, F


What percent of the students are taller than the shortest girl and shorter than the tallest boy?
Shortest girl is A and the tallest boy is Z
As we can see from the above diagram, there are 10 such students

10/16 = 5/8 = 62.5%

Answer: C

Cheers,
Brent

Thank you so much.

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