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The diagonal of a rectangle
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05 Dec 2019, 12:13
05 Dec 2019, 12:13
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Expert Reply
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Question Stats:
75% (00:38) correct
24% (00:11) wrong based on 29 sessions
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Quantity A |
Quantity B |
The diagonal of a rectangle |
Half the perimeter of the same rectangle |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: The diagonal of a rectangle
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15 Jan 2020, 07:32
15 Jan 2020, 07:32
Carcass wrote:
Quantity A |
Quantity B |
The diagonal of a rectangle |
Half the perimeter of the same rectangle |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Attachment:
#greprepclub The diagonal of a rectangle.jpg [ 13.35 KiB | Viewed 3706 times ]
Plz refer to diag. above
Let us take a rectangle ABCD of length 4 cm and breadth 3 cm
Diagonal of the rectangle BC = \(\sqrt{( 3^2 + 4^2)} = 5\)
Now,
Half the perimeter of the same rectangle = \(\frac{{2 * ( 3 + 4)}}{ 2} = 7\)
Therefore, QTY B > QTY A
Option A
Re: The diagonal of a rectangle
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16 Jan 2020, 07:13
16 Jan 2020, 07:13
let the width be x, hence for a rectangle length can be x+1
half the perimeter = x+x+1
while the diagonal, using pythagoras = sqr(2x^2+1),
try any value of x, The quantity in Column B is greater will hold
half the perimeter = x+x+1
while the diagonal, using pythagoras = sqr(2x^2+1),
try any value of x, The quantity in Column B is greater will hold
