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If Jan starts walking from Town X to Town Y, a distance of 9
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27 Dec 2019, 11:31
27 Dec 2019, 11:31
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Question Stats:
85% (01:54) correct
15% (01:40) wrong based on 20 sessions
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If Jan starts walking from Town X to Town Y, a distance of 9 miles, at 2 miles per hour at the same time as Terry starts walking from Town Y to Town X at 3 miles per hour along the same path as Jan, how many miles apart will Jan and Terry be exactly 42 minutes before they meet?
A. 2.0
B. 2.5
C. 3.0
D. 3.5
E. 4.0
Kudos for the right answer and explanation
A. 2.0
B. 2.5
C. 3.0
D. 3.5
E. 4.0
Kudos for the right answer and explanation
Re: If Jan starts walking from Town X to Town Y, a distance of 9
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28 Dec 2019, 06:08
28 Dec 2019, 06:08
3
X----------------Y
d = 9 miles
Jan starts from X at a speed of 2 miles per hour and Terry starts from Y at a speed of 3 miles per hour.
Time taken when they will meet \(\frac{9}{2+3}\) = 1.8 hours = 108 min.
Total distance covered by Jan = 2*1.8 = 3.6 miles
Total distance covered by Terry = 3*1.8 = 5.4 miles
Now each person travels for 108 min so we need to find the distance between them 42 minutes before they meet.
It means they each will travel for 66 minutes.
Now, Jan covers a distance of 2.2 miles in 66 minutes and Terry covers a distance of 3.3 miles in 66 minutes.
Distance remaining between them is \((3.6 - 2.2) + (5.4-3.3)\) = 1.4 + 2.1 = 3.5
OA, D
d = 9 miles
Jan starts from X at a speed of 2 miles per hour and Terry starts from Y at a speed of 3 miles per hour.
Time taken when they will meet \(\frac{9}{2+3}\) = 1.8 hours = 108 min.
Total distance covered by Jan = 2*1.8 = 3.6 miles
Total distance covered by Terry = 3*1.8 = 5.4 miles
Now each person travels for 108 min so we need to find the distance between them 42 minutes before they meet.
It means they each will travel for 66 minutes.
Now, Jan covers a distance of 2.2 miles in 66 minutes and Terry covers a distance of 3.3 miles in 66 minutes.
Distance remaining between them is \((3.6 - 2.2) + (5.4-3.3)\) = 1.4 + 2.1 = 3.5
OA, D
Carcass wrote:
If Jan starts walking from Town X to Town Y, a distance of 9 miles, at 2 miles per hour at the same time as Terry starts walking from Town Y to Town X at 3 miles per hour along the same path as Jan, how many miles apart will Jan and Terry be exactly 42 minutes before they meet?
A. 2.0
B. 2.5
C. 3.0
D. 3.5
E. 4.0
Kudos for the right answer and explanation
A. 2.0
B. 2.5
C. 3.0
D. 3.5
E. 4.0
Kudos for the right answer and explanation
Re: If Jan starts walking from Town X to Town Y, a distance of 9
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14 Feb 2021, 19:37
14 Feb 2021, 19:37
Hi,
As we know that Jan and Terry are walking in the same direction the distance both of them together travel in an hour is the total distance travelled in one hour i.e. 2 miles(Jan travels in 1 hour)+3 miles (Terry travels in 1 hour)=5 miles/hr
Thus, the total time required to meet= 1 hr 48 mins (9miles*60mins/5 )
Now, in order to find the distance left 42 minutes before they meet. We know the two of the travel 5miles in 60 mins
Dividing 5 by 60 will give us the what distance the two travel in 1 min.
5/60=0.0833
Multiplying 0.0833 by 42 as we need the distance 42 mins before they meet
0.08333*42= 3.5 miles
IMO D
Hope this helps!
As we know that Jan and Terry are walking in the same direction the distance both of them together travel in an hour is the total distance travelled in one hour i.e. 2 miles(Jan travels in 1 hour)+3 miles (Terry travels in 1 hour)=5 miles/hr
Thus, the total time required to meet= 1 hr 48 mins (9miles*60mins/5 )
Now, in order to find the distance left 42 minutes before they meet. We know the two of the travel 5miles in 60 mins
Dividing 5 by 60 will give us the what distance the two travel in 1 min.
5/60=0.0833
Multiplying 0.0833 by 42 as we need the distance 42 mins before they meet
0.08333*42= 3.5 miles
IMO D
Hope this helps!
