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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
In the same amount of time a new production assembly robot c
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02 Jan 2020, 00:00
02 Jan 2020, 00:00
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In the same amount of time a new production assembly robot can assemble 8 times as many transmissions as an old assembly line. If the new robot can assemble x transmissions per hour, how many transmissions can the new robot and the old assembly line produce together in five days of round-the-clock production?
(A) 45x/8
(B) 15x
(C) 135x/8
(D) 135x
(E) 1080x
(A) 45x/8
(B) 15x
(C) 135x/8
(D) 135x
(E) 1080x
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Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1111
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Re: In the same amount of time a new production assembly robot c
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02 Jan 2020, 08:17
02 Jan 2020, 08:17
1
This question is based on Rate and Work.
The formula sued in these problems is Rate * Time = Work done
If two people work together then their rates get added up.
Let rate of old machine be r
Rate of new machine is given as x transmissions/hour (let's denote Transmission/hour as TPH)
Work done by New machine in some time (let's say t) is 8 times the work done by old machine in same time (t)
Using the formula Rate * time = work done
Rate of new machine * t = 8 * Rate of old machine * t
x*t = 8*r*t
=> r = x/8 TPH
Now, when both of them are working together then their rates get added up.
So combined rate = x + r = x + x/8 = 9x/8 TPH
Work done by both together in 5 days= combined rate * 5 * 24 (1 day has 24 hours) = combined rate * 120 = 9*x/8 * 120 = 9x*15 = 135x
So, answer will be D
Hope it helps!
The formula sued in these problems is Rate * Time = Work done
If two people work together then their rates get added up.
Let rate of old machine be r
Rate of new machine is given as x transmissions/hour (let's denote Transmission/hour as TPH)
Work done by New machine in some time (let's say t) is 8 times the work done by old machine in same time (t)
Using the formula Rate * time = work done
Rate of new machine * t = 8 * Rate of old machine * t
x*t = 8*r*t
=> r = x/8 TPH
Now, when both of them are working together then their rates get added up.
So combined rate = x + r = x + x/8 = 9x/8 TPH
Work done by both together in 5 days= combined rate * 5 * 24 (1 day has 24 hours) = combined rate * 120 = 9*x/8 * 120 = 9x*15 = 135x
So, answer will be D
Hope it helps!
Re: In the same amount of time a new production assembly robot c
[#permalink]
22 Jun 2022, 05:21
22 Jun 2022, 05:21
Hello from the GRE Prep Club BumpBot!
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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