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Re: |x| y > x |y| [#permalink]
1
Tejas2805 wrote:
x|y| < y|x|

Can be written as,

x/|x| < y/|y|

as these values can be +1 or -1 only,

y > 0 and x < 0,

Therefore B has to be greater



I DIDNOT UNDERSTAND SIR YOUR APPROACH. HOW CAN YOU DO x/|x| < y/|y| THIS?
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Re: |x| y > x |y| [#permalink]
Hello from the GRE Prep Club BumpBot!

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Re: |x| y > x |y| [#permalink]
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