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The probability that Gary will eat eggs
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Updated on: 13 Dec 2021, 23:45
Updated on: 13 Dec 2021, 23:45
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Question Stats:
71% (00:47) correct
28% (00:55) wrong based on 21 sessions
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The probability that Gary will eat eggs for breakfast on any given day is 3/7. The probability that Gary will eat cereal for breakfast on any given day is 4/7. Gary never has both eggs and cereal for breakfast on the same day.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Source: Manhattan Prep
Quantity A |
Quantity B |
Probability that Gary eats eggs or cereal for breakfast on a particular day |
1 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Source: Manhattan Prep
Re: The probability that Gary will eat eggs
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23 Jul 2016, 12:07
23 Jul 2016, 12:07
3
Expert Reply
Solution
Here we have 2 events:
A: Eating Egg. P(A)=\(\frac{3}{7}\)
B: Eating Cereal. P(B) =\(\frac{4}{7}\)
A and B: Eating both Eggs and Cereals. P(A and B) = \(0\)
P(A or B)= P(A) + P(B) - P(A and B)
= \(\frac{3}{7} + \frac{4}{7} - 0\) = 1
Hence P(A or B)= 1. Thus Option C is correct.
Here we have 2 events:
A: Eating Egg. P(A)=\(\frac{3}{7}\)
B: Eating Cereal. P(B) =\(\frac{4}{7}\)
A and B: Eating both Eggs and Cereals. P(A and B) = \(0\)
P(A or B)= P(A) + P(B) - P(A and B)
= \(\frac{3}{7} + \frac{4}{7} - 0\) = 1
Hence P(A or B)= 1. Thus Option C is correct.
The probability that Gary will eat eggs
[#permalink]
13 Dec 2021, 23:47
13 Dec 2021, 23:47
Expert Reply
