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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
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adeel wrote:
sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

Quantity A
Quantity B
The proportion of the class that received a score less than John’s score
The proportion of the class that scored equal to or greater than Jane’s score


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Solution : It is not mentioned in the question whether a normal distribution or not


It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x.
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
Simon wrote:
adeel wrote:
sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

Quantity A
Quantity B
The proportion of the class that received a score less than John’s score
The proportion of the class that scored equal to or greater than Jane’s score


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Solution : It is not mentioned in the question whether a normal distribution or not


It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x.



Still do not get how both quantities are equal.
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
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I do not agree with the answer because

- the first question asks "a score less than John’s score", hence less than 32, but not including 32 itself
- the second asks "equal to or greater than Jane’s score", hence 100-68=32, including 68th percentile itself

as a result, we need to compare "less than 32" with "exactly 32"
so the answer should be B
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
It is given that john scored a 32nd percentile and not 32% or 32 marks. By definition, 32 percentile means that 32% of the total test takers were below the john's score(which is not given). Similarly,100-68= 32% of total test takers were either equal or above the jane's score.
Hence , the quantities are equal.
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
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question phrased weirdly
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Jane scored in the 68th percentile on a test, and John score [#permalink]
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What if there are 100 students. Jane got grade of 40, and another group of people got 40. So technically it is possible that only one student out of 100 got less than Jane, like if one got grade of 10 and the next 35 got 32 like Jane. So it is possible that A=1 and B=30
So why the answer in the book is C?

Assume that the next grades possible:
{1, 30, 30, 30,..., 98, 99, 100}
According to this list, Jane will have only one smaller grade (1), while John will have three (98, 99, 100)

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Jane scored in the 68th percentile on a test, and John score [#permalink]
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