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A certain band will perform 15 different songs in random ord
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28 Dec 2019, 13:16
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A certain band will perform 15 different songs in random order, and no song will be performed twice. If 9 of the songs are new, what is the probability that the first 2 songs that the band performs will both be new?
Re: A certain band will perform 15 different songs in random ord
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29 Dec 2019, 01:00
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We have to select two songs such that both of them are new. Total new songs available = 9 Probability = \(\frac{9C2}{15C2}\) = \(\frac{9*8}{15*14}\)
Probability = \(\frac{12}{35}\)
Carcass wrote:
A certain band will perform 15 different songs in random order, and no song will be performed twice. If 9 of the songs are new, what is the probability that the first 2 songs that the band performs will both be new?
Re: A certain band will perform 15 different songs in random ord
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09 Jan 2020, 01:22
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Carcass wrote:
A certain band will perform 15 different songs in random order, and no song will be performed twice. If 9 of the songs are new, what is the probability that the first 2 songs that the band performs will both be new?
Re: A certain band will perform 15 different songs in random ord
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20 Apr 2020, 16:36
I know everyone is doing it the 9c2/15c2 way..but it doesn't make sense to me this way since order wouldn't matter for the first two as long as they were new. So those would actually be combinations, no? (9*8)/2! * (15*14)/2! which doesn't yield correct answer.
I think its just a reg probability question favorable/total= 9/15 * 8/14 = 12/35
But I'm not sure.
gmatclubot
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