GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A certain boat sales lot sells both sailboats and boats that
[#permalink]
08 Jan 2020, 14:50
08 Jan 2020, 14:50
1
13
Bookmarks
00:00
Question Stats:
40% (03:44) correct
60% (02:58) wrong based on 90 sessions
Hide Show timer Statistics
A certain boat sales lot sells both sailboats and boats that are not sailboats. 25% of the boats are used sailboats. Of non-sailboats, \(\frac{3}{5}\) are new. If 33% of all boats are used, approximately what percentage of the sailboats are new?
(A) 31%
(B) 33%
(C) 67%
(D) 68%
(E) 69%
(A) 31%
(B) 33%
(C) 67%
(D) 68%
(E) 69%
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1115
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Re: A certain boat sales lot sells both sailboats and boats that
[#permalink]
11 Jan 2020, 10:11
11 Jan 2020, 10:11
5
1
This question can be solved using overlapping sets 2x2 matrix. PFA The first image which talks about the things which are given in the question.
Now we are asked to find what percentage of the sailboats are new, which is nothing but \(\frac{Sailboats Which Are New }{ Total Sailboats}*100%\)
Now, see the second image attached. Let's calculate Used Non Sailboats. Using the Used column we will get number of used non-sailboats as 33-25 = 8
Using the Non-sailboat row we will get number of used non-sailboats as x = 3x/5 = 2x/5
=> 2x/5 = 8 => x = 20
So, Total Sailboats = 100-x = 100-20 = 80
New Sailboats = Total Sailboats - Used = 80 - 25 = 55
So, percentage of the sailboats are new = \(\frac{Sailboats Which Are New }{ Total Sailboats}\) = \(\frac{55 }{ 80}* 100%\) = 68.75% ~ 69%.
So, Answer will be E.
Hope it helps!
Now we are asked to find what percentage of the sailboats are new, which is nothing but \(\frac{Sailboats Which Are New }{ Total Sailboats}*100%\)
Now, see the second image attached. Let's calculate Used Non Sailboats. Using the Used column we will get number of used non-sailboats as 33-25 = 8
Using the Non-sailboat row we will get number of used non-sailboats as x = 3x/5 = 2x/5
=> 2x/5 = 8 => x = 20
So, Total Sailboats = 100-x = 100-20 = 80
New Sailboats = Total Sailboats - Used = 80 - 25 = 55
So, percentage of the sailboats are new = \(\frac{Sailboats Which Are New }{ Total Sailboats}\) = \(\frac{55 }{ 80}* 100%\) = 68.75% ~ 69%.
So, Answer will be E.
Hope it helps!
Attachments
File comment: Image-1
img1.jpg [ 124.15 KiB | Viewed 6508 times ]
File comment: Image-2
img2.jpg [ 136.43 KiB | Viewed 6483 times ]
General Discussion
Re: A certain boat sales lot sells both sailboats and boats that
[#permalink]
14 Jan 2020, 03:00
14 Jan 2020, 03:00
2
huda wrote:
A certain boat sales lot sells both sailboats and boats that are not sailboats. 25% of the boats are used sailboats. Of non-sailboats, \(\frac{3}{5}\) are new. If 33% of all boats are used, approximately what percentage of the sailboats are new?
(A) 31%
(B) 33%
(C) 67%
(D) 68%
(E) 69%
(A) 31%
(B) 33%
(C) 67%
(D) 68%
(E) 69%
Sorry to reply the answer in the form of an image but have to as it's a Venn diagram question. Please could the author check the answer as my answer is 67%. The 3/5th of Non sail boats information is not required.
Attachments
WhatsApp Image 2020-01-14 at 4.27.52 PM.jpeg [ 65.39 KiB | Viewed 6440 times ]
