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Nancy purchased a consignment of c red roses at a cost of d
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16 May 2019, 16:29
16 May 2019, 16:29
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65% (01:45) correct
34% (01:32) wrong based on 91 sessions
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Nancy purchased a consignment of c red roses at a cost of d dollars. She made bouquets with the roses and each bouquet contained d roses. She sold each bouquet at a price of c dollars. Overall, she made a profit.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
c |
d |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Nancy purchased a consignment of c red roses at a cost of d
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14 Jan 2020, 06:39
14 Jan 2020, 06:39
1
Let's Calculate Cost of Each Bouquet
c red roses at a cost of d dollars
=> Cost of 1 Rose = d/c dollars
=> Cost of 1 bouquet = d roses = d * d/c dollars = \(\frac{ d^2}{c}\) dollars
=> Selling Price of 1 bouquet = c dollars and she made a profit => Selling price > Cost price
c > \(\frac{ d^2}{c}\)
As c is positive so we can cross multiply both sides by c and we get
\( c^2 > d^2\)
As, both d and c are positive so we can take square root on both the sides and we will get
c > d
So, Quantity A is greater than Quantity B
So, Answer is A
Hope it helps!
c red roses at a cost of d dollars
=> Cost of 1 Rose = d/c dollars
=> Cost of 1 bouquet = d roses = d * d/c dollars = \(\frac{ d^2}{c}\) dollars
=> Selling Price of 1 bouquet = c dollars and she made a profit => Selling price > Cost price
c > \(\frac{ d^2}{c}\)
As c is positive so we can cross multiply both sides by c and we get
\( c^2 > d^2\)
As, both d and c are positive so we can take square root on both the sides and we will get
c > d
So, Quantity A is greater than Quantity B
So, Answer is A
Hope it helps!
Re: Nancy purchased a consignment of c red roses at a cost of d
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23 Nov 2020, 13:03
23 Nov 2020, 13:03
1
The other response is a great way to see how to translate the problem from English to math. Plugging in will work here too. C=100 and d=1 works very well for this lady, but as soon as we test to see if d can be greater than c, it becomes clear that she cannot make a bouquet, let alone a profit. I tried c=10 and d=20 and she cannot even make the bouquet.
