Addition and subtraction in inequality in any case is accepted:
(A) 6c-3 ? (B)3c-5 just solve it like algebraic expressions.
3C ? -2 Simple addition and subtraction on both sides.
C ? -2/3 Dividing by 3(being positive no.) on both sides is accepted.
Since c<–1, (B) is the answer.

We can solve this question using matching operations

Given:
Quantity A: \(6c-3\)
Quantity B: \(3c-5\)

Add \(3\) to both quantities to get:
Quantity A: \(6c\)
Quantity B: \(3c-2\)

Subtract \(3c\) from both quantities to get:
Quantity A: \(3c\)
Quantity B: \(-2\)

Divide both quantities by \(3\) to get:
Quantity A: \(c\)
Quantity B: \(-\frac{2}{3}\)

Since \(-1 < -\frac{2}{3}\), and since it's given that \(c < –1\), we can combine both inequalities to get: \(c < -1 < -\frac{2}{3}\)
This means \(c < -\frac{2}{3}\), so Quantity B is greater.

Answer: B


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Even if \(C = -1 \)(extreme value)

Quantity A is \(6(-1) - 3\) compared to Quantity B \(3(-1) - 5\)

\(-6 - 3\) compared to \(-3 - 5\)

\(- 9 \) < \(-8\)

When \(C < -1\), we can expect this inequality to hold even more so.

Therefore, answer is Quantity B.