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x and y are both integers
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20 Jan 2020, 07:00
20 Jan 2020, 07:00
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x and y are both integers
\(xy \neq 0\)
\(x < y\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\(xy \neq 0\)
\(x < y\)
Quantity A |
Quantity B |
\(x^2\) |
\(y^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
x and y are both integers
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20 Jan 2020, 08:01
20 Jan 2020, 08:01
2
Carcass wrote:
x and y are both integers
\(xy \neq 0\)
\(x < y\)
\(xy \neq 0\)
\(x < y\)
Quantity A |
Quantity B |
\(x^2\) |
\(y^2\) |
Let's test some possible values of x and y
case i: Since \(x < y\), one possible pair of values is \(x=1\) and \(y=2\)
We get:
Quantity A: \(x^2 = 1^2 = 1\)
Quantity B: \(y^2 = 2^2 = 4\)
In this case, Quantity B is greater
case ii: Since \(x < y\), another possible pair of values is \(x=-2\) and \(y=1\)
We get:
Quantity A: \(x^2 = (-2)^2 = 4\)
Quantity B: \(y^2 = 1^2 = 1\)
In this case, Quantity A is greater
Answer: D
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Re: x and y are both integers
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25 Feb 2020, 19:15
25 Feb 2020, 19:15
1
In these kind of questions I would suggest to plug really easy value and the first one must be a value that could get same value for both.
xy are not 0
Hence x could be -1 and y could be 1, as they are squaring the numbers, the result will be 1 for both.
Then just plus 100 for example for y and -1 for x.
D
xy are not 0
Hence x could be -1 and y could be 1, as they are squaring the numbers, the result will be 1 for both.
Then just plus 100 for example for y and -1 for x.
D
