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Clement walks around an oval-shaped track at a constant rate
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19 Jan 2020, 03:32
19 Jan 2020, 03:32
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89% (01:44) correct
10% (02:38) wrong based on 29 sessions
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Clement walks around an oval-shaped track at a constant rate of 50 seconds per lap. If 18 laps equal a mile, now many miles does Clement walk in 54 minutes?
A. \(2\)
B. \(2 \frac{1}{2}\)
C. \(3\)
D. \(3 \frac{3}{5}\)
E. \(4 \frac{1}{3}\)
Kudos for the right answer and explanation
A. \(2\)
B. \(2 \frac{1}{2}\)
C. \(3\)
D. \(3 \frac{3}{5}\)
E. \(4 \frac{1}{3}\)
Kudos for the right answer and explanation
Re: Clement walks around an oval-shaped track at a constant rate
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21 Jan 2020, 21:58
21 Jan 2020, 21:58
1
Total time walked = 54 mins.
Total time walked in seconds = 54 * 60.
laps completed = (54 * 60)/50.
18 laps = 1 mile.
Total miles completed = (54 * 60)/50 * 1/18 = 18/5 => 3 3/5.
Therefore D is the answer.
Total time walked in seconds = 54 * 60.
laps completed = (54 * 60)/50.
18 laps = 1 mile.
Total miles completed = (54 * 60)/50 * 1/18 = 18/5 => 3 3/5.
Therefore D is the answer.
Re: Clement walks around an oval-shaped track at a constant rate
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08 Feb 2021, 15:03
08 Feb 2021, 15:03
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
