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Let x, y, and z be non-zero numbers such that the average (a
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29 Jan 2020, 10:22
29 Jan 2020, 10:22
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Let x, y, and z be non-zero numbers such that the average (arithmetic mean) of x and twice y is equal to the average (arithmetic mean) of y and twice z. What is the average (arithmetic mean) of x and y?
A. \(\frac{z}{2}\)
B. z
C. 2z
D. z-x
E. z-y
Kudos for the right answer and explanation
A. \(\frac{z}{2}\)
B. z
C. 2z
D. z-x
E. z-y
Kudos for the right answer and explanation
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Re: Let x, y, and z be non-zero numbers such that the average (a
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29 Jan 2020, 10:48
29 Jan 2020, 10:48
1
Carcass wrote:
Let x, y, and z be non-zero numbers such that the average (arithmetic mean) of x and twice y is equal to the average (arithmetic mean) of y and twice z. What is the average (arithmetic mean) of x and y?
A. \(\frac{z}{2}\)
B. z
C. 2z
D. z-x
E. z-y
Kudos for the right answer and explanation
A. \(\frac{z}{2}\)
B. z
C. 2z
D. z-x
E. z-y
Kudos for the right answer and explanation
We know that: Average of x and 2y is equal to the average of y and 2z
\(=> (x + 2y)/2 = (y + 2z)/2\)
\(=> x + y = 2z\)
\(=> (x + y)/2 = z\)
=> Average of x and y is equal to z
Answer B
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Re: Let x, y, and z be non-zero numbers such that the average (a
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05 Aug 2022, 21:59
05 Aug 2022, 21:59
Theory
The average (arithmetic mean) of x and twice y is equal to the average (arithmetic mean) of y and twice z
Average of x and 2y = \(\frac{Sum}{2}\) = \(\frac{x + 2y}{2}\)
Average of y and 2z = \(\frac{Sum}{2}\) = \(\frac{y + 2z}{2}\)
Average of x and 2y = Average of y and 2z
=> \(\frac{x + 2y}{2}\) = \(\frac{y + 2z}{2}\)
=> x + 2y = y + 2z
=> x + 2y-y = 2z
=> x + y = 2z
=> \(\frac{x + y}{2}\) = z
=> Mean of x and y = z
So, Answer will be B.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
- ➡ Average or Arithmetic Mean = Sum of all the Values / Total Number of Values
The average (arithmetic mean) of x and twice y is equal to the average (arithmetic mean) of y and twice z
Average of x and 2y = \(\frac{Sum}{2}\) = \(\frac{x + 2y}{2}\)
Average of y and 2z = \(\frac{Sum}{2}\) = \(\frac{y + 2z}{2}\)
Average of x and 2y = Average of y and 2z
=> \(\frac{x + 2y}{2}\) = \(\frac{y + 2z}{2}\)
=> x + 2y = y + 2z
=> x + 2y-y = 2z
=> x + y = 2z
=> \(\frac{x + y}{2}\) = z
=> Mean of x and y = z
So, Answer will be B.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
