One option here is to expand and simplify Quantity A. The problem is that this approach could take a while.

Instead, I'm going to test some values

case i: Since $pq \neq 0$, it COULD be the case that $p = -1$ and $q = 1$
We get:
Quantity A: $(p+q)^3=((-1)+1)^3=0^3=0$
Quantity B: $p^3+q^3=(-1)^3+1^3=(-1)+1=0$
In this case, the two quantities are equal

case ii: Alternatively, it could be the case that $p = 1$ and $q = 1$
We get:
Quantity A: $(p+q)^3=(1+1)^3=2^3=8$
Quantity B: $p^3+q^3=1^3+1^3=1+1=2$
In this case, Quantity A is greater

Answer: D

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