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In the rectangle above, AB = x feet, BC = y feet, and AE = F
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01 Feb 2020, 09:15
01 Feb 2020, 09:15
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Question Stats:
83% (01:38) correct
16% (00:46) wrong based on 6 sessions
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In the rectangle above, AB = x feet, BC = y feet, and AE = FC = 2 feet. What is the area of triangle DEF, in square feet?
A. \(\frac{xy}{2} + 2 \)
B. \(\frac{xy}{2} - x -y -2\)
C. \(\frac{xy}{2} -x-y+2
\)
D. \(xy-2x-2y-4\)
E. \(xy-2x-2y+4\)
Kudos for the right answer and explanation
Re: In the rectangle above, AB = x feet, BC = y feet, and AE = F
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03 Feb 2020, 10:32
03 Feb 2020, 10:32
1
Area of the triangle: 1/2 * length * height --> since it is a rectangle, vertix ADC is a right angle, hence DE is the height
--> 1/2 * (x-2) * (y-2) = 1/2 *xy -x -y +2 --> C is the right answer
--> 1/2 * (x-2) * (y-2) = 1/2 *xy -x -y +2 --> C is the right answer
gmatclubot
Re: In the rectangle above, AB = x feet, BC = y feet, and AE = F [#permalink]
03 Feb 2020, 10:32
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