alamin wrote:
6 ≤ |x| ≤ 8
1 ≤ |y| ≤ 2
3 ≤ |z| ≤ 4
If x, y, and z satisfy the inequalities shown, what is the least possible value of |x+y+z |?
A. 0
B. 1
C. 2
D. 3
E. 4
If 6 ≤ |x| ≤ 8 , then EITHER 6 ≤ x ≤ 8 OR -8 ≤ x ≤ -6
If 1 ≤ |y| ≤ 2 , then EITHER 1 ≤ y ≤ 2 OR -2 ≤ y ≤ -1
If 3 ≤ |x| ≤ 4 , then EITHER 3 ≤ z ≤ 4 OR -4 ≤ z ≤ -3
What is the least possible value of |x + y + z|?If x = -6, y = 2 and z = 4, then |x + y + z| = |(-6) + 2 + 4| = 0
Since 0 is the smallest answer choice, the correct answer must be A
Cheers,
Brent