Carcass wrote:
A pot of soup was divided equally into two bowls. If Manuel ate \(\frac{1}{4}\) of one of the bowls of soup and \(\frac{2}{5}\) of the other bowl of soup, what fraction of the entire pot of soup did Manuel eat?
Give your answer as a fraction.
To make things easier on ourselves, that's assign a "nice" value to the total volume of soup in the entire pot.
Let's say the pot contains
40 gallons of soup
So when the soup is divided
equally into two bowls, EACH BOWL contains
20 gallons of soup
If Manuel ate \(\frac{1}{4}\) in one bowl, then the amount he ate = \(\frac{1}{4}\) of
20 gallons =
5 gallons
If Manuel ate \(\frac{2}{5}\) of the other bowl, then the amount he ate = \(\frac{2}{5}\) of
20 gallons =
8 gallons
So the TOTAL amount of soup eaten =
5 gallons +
8 gallons =
13 gallons
What fraction of the entire pot of soup did Manuel eat?The fraction of soup eaten =
13/
40Answer: 13/40
Cheers,
Brent