GreenlightTestPrep wrote:
In a certain the sequence, tn=tn−1tn−2 for n>2. If t1=3 and t2=5, then what is the product of the first 54 terms of the sequence?
A) 3/5
B) 1/3
C) 1
D) 5/3
E) 5
Given:
tn=tn−1tn−2t1=3t2=5So,
t3=t3−1t3−2=t2t1=53t4=t4−1t4−2=t3t2=(53)5=13t5=15t6=35t7=3t8=5.
.
.
As we can see, the
pattern repeats itself every 6 terms.
Also notice that the product of the first six terms is 1.
This means the product of the NEXT six terms must also be 1
And the product of the six terms AFTER THAN must be 1 as well
The first 54 terms will consist of nine groups consisting of 6 terms each.
So, the product of the first 54 terms will equal the product of nine 1's
So, the product must equal 1
Answer: C
Cheers,
Brent