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QOTD#11 x = (z –1)^2 y = (z +1)^2

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sandy
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QOTD#11 x = (z –1)^2 y = (z +1)^2 [#permalink] New post   19 Aug 2016, 02:46
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\(x = (z -1)^2\)
\(y = (z +1)^2\)

Quantity A
Quantity B
The average (arithmetic mean) of x and y
\(z^2\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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Question: 4
Page: 149 - 150
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A
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GreenlightTestPrep
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Re: QOTD#11 x = (z –1)^2 y = (z +1)^2 [#permalink] New post   19 Aug 2016, 05:51
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sandy wrote:
\(x = (z -1)^2\)
\(y = (z +1)^2\)

Quantity A
Quantity B
Arithmetic Mean of x and y
[fraction]z^2[/fraction]


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Practice Questions
Question: 4
Page: 149 - 150


Explanation

Quantity A: average of x and y
Quantity B: z²

Quantity A: [(z-1)² + (z+1)²]/2
Quantity B: z²

Quantity A: [(z² - 2z + 1) + (z² + 2z + 1)]/2
Quantity B: z²

Quantity A: [2z² + 2]/2
Quantity B: z²

Quantity A: z² + 1
Quantity B: z²

Subtract z² from both quantities to get:
Quantity A: 1
Quantity B: 0

Answer:
Show: ::
A
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Re: QOTD#11 x = (z 1)^2 y = (z +1)^2 [#permalink] New post   30 Jul 2022, 04:08
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: QOTD#11 x = (z 1)^2 y = (z +1)^2 [#permalink]
30 Jul 2022, 04:08
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