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Re: If the equation, kx^2+4x+(5-k)=0 [#permalink]
pprakash786 wrote:
Can someone please explain this?


Not sure if me posting sent you a notification but lmk if you have any questions about the explanation

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Re: If the equation, kx^2+4x+(5-k)=0 [#permalink]
Is there another way to solve this without using the quadratic formula?
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Re: If the equation, kx^2+4x+(5-k)=0 [#permalink]
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greenpistachio wrote:
Is there another way to solve this without using the quadratic formula?


If there is another way, it will be much more complicated than applying "b² - 4ac > 0" concept from the quadratic formula.

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Re: If the equation, kx^2+4x+(5-k)=0 [#permalink]
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Use quadratic formula
b^2 - 4ac > 0
4^2 - 4(K)(5 - K) > 0
16 - 4K (5-K) > 0
16 - 20K + 4K^2 > 0
divide by 4 ==> 4 - 5K + K^2 > 0
equals to K^2 - 5K + 4 > 0
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Re: If the equation, kx^2+4x+(5-k)=0 [#permalink]
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