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Lines q and r in the figure shown are parallel lines cut by
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30 Mar 2020, 11:59
30 Mar 2020, 11:59
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96% (00:48) correct
3% (01:47) wrong based on 29 sessions
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#greprepclub Lines q and r in the figure shown are parallel lines cut by transversal p.jpg [ 14.37 KiB | Viewed 2856 times ]
Lines q and r in the figure shown are parallel lines cut by transversal p. What is the sum of the measure of angles a, d, f, and g in degrees?
Show: :: OA- degree
360
Re: Lines q and r in the figure shown are parallel lines cut by
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30 Mar 2020, 21:54
30 Mar 2020, 21:54
1
Opposite angles are equal. Thus a=d and f=g, here we can see that d and f are complimentary angles, which sum is equal to 180. Hence, on adding a,d,f,g, the sum must be 360.
Re: Lines q and r in the figure shown are parallel lines cut by
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24 Apr 2020, 07:52
24 Apr 2020, 07:52
1
Here for the given question, we will use the Opposite angles equal property.
we can see that,
a=d and f=g
Also, d and f are complementary angles, which have a sum equal to 180. ( d + f = 180)
Also, a and g are exterior angles with a + g = 180
Thus, (a+g) + (d+f) = 180 + 180 = 360
Hence, on adding a,d,f,g, the sum must be 360.
we can see that,
a=d and f=g
Also, d and f are complementary angles, which have a sum equal to 180. ( d + f = 180)
Also, a and g are exterior angles with a + g = 180
Thus, (a+g) + (d+f) = 180 + 180 = 360
Hence, on adding a,d,f,g, the sum must be 360.
