Carcass wrote:
The present age of a father is 3 years more than three times the age of his son. Three years hence , father's age will be 10 years more than twice the age of the son. Present age of the father is ?
A. 9
B. 10
C. 30
D. 33
E. 35
Kudos for the right answer and explanation
The present age of a father is 3 years more than three times the age of his sonLet x = the PRESENT age of the son
So, 3x + 3 = the PRESENT age of the father
So, x +
3 = the son's age IN THREE YEARS
And 3x + 3 +
3 = the father's age IN THREE YEARS
Three years hence , father's age will be 10 years more than twice the age of the sonIn other words: (father's age in 3 years) = 2(son's age in 3 years) + 10
In other words: (3x + 3 +
3) = 2(x +
3) + 10
Simplify: 3x + 6 = 2x + 16
Subtract 2x from both sides: x + 6 = 16
Subtract 6 from both sides: x = 10
This means the son's PRESENT age is 10 years old
Since 3x + 3 = the PRESENT age of the father, the father's present age = 3(10) + 3 = 33
Answer: D
Cheers,
Brent