GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
Director
Joined: 16 May 2014
Posts: 590
Given Kudos: 0
GRE 1: Q165 V161
GRE Math Challenge #7-David drove to work at an average
[#permalink]
15 Sep 2014, 22:03
15 Sep 2014, 22:03
2
Expert Reply
6
Bookmarks
00:00
Question Stats:
65% (01:37) correct
34% (01:34) wrong based on 198 sessions
Hide Show timer Statistics
David drove to work at an average (arithmetic mean) speed of 45 miles per hour. After work, David drove home at an average speed of 60 miles per hour. If David spent a total of 2 hours commuting to and from work, how many miles does David drive to work?
A)48
B)\(\frac{256}{5}\)
C)\(\frac{360}{7}\)
D)\(\frac{105}{2}\)
E)\(\frac{160}{3}\)
A)48
B)\(\frac{256}{5}\)
C)\(\frac{360}{7}\)
D)\(\frac{105}{2}\)
E)\(\frac{160}{3}\)
Re: GRE Math Challenge #7-David drove to work at an average
[#permalink]
02 Feb 2018, 08:55
02 Feb 2018, 08:55
3
The total distance going from home to work = total distance going from work to home
In the 1st case David drove @ an average speed of 45 miles per hour so distance \(d = 45 h1\)where \(h1\)is the time taken to complete the distance
In the 2nd case David drove @ an average speed of 60 miles per hour so distance \(d = 60 h2\)where \(h2\)is the time taken to complete the return journey from work to home
Given,
\(h1 + h2 = 2\)
we get,\(h1 = 2 - h2\)
Since distance is equal for going to work from home and coming back to home from work
\(45h1 = 60h2\)
hence, \(45(2 - h2) = 60 h2\)
solve for h2 it should equal\(\frac{90}{105}\)
Solve for D by replacing value of h2 in the eqn \(60* h2\)
\(d =\frac{360}{7}\)
(C)
In the 1st case David drove @ an average speed of 45 miles per hour so distance \(d = 45 h1\)where \(h1\)is the time taken to complete the distance
In the 2nd case David drove @ an average speed of 60 miles per hour so distance \(d = 60 h2\)where \(h2\)is the time taken to complete the return journey from work to home
Given,
\(h1 + h2 = 2\)
we get,\(h1 = 2 - h2\)
Since distance is equal for going to work from home and coming back to home from work
\(45h1 = 60h2\)
hence, \(45(2 - h2) = 60 h2\)
solve for h2 it should equal\(\frac{90}{105}\)
Solve for D by replacing value of h2 in the eqn \(60* h2\)
\(d =\frac{360}{7}\)
(C)
