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If a half-full 4-inch by 2-inch by 8-inch box of soymilk is
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19 Sep 2018, 17:52
19 Sep 2018, 17:52
Expert Reply
00:00
Question Stats:
75% (01:21) correct
25% (01:10) wrong based on 48 sessions
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If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured into a right circular cylindrical glass with radius 2 inches, how many inches high will the soymilk reach? (Assume that the capacity of the glass is greater than the volume of the soymilk.)
(A) \(8\)
(B) \(16\)
(C) \(\frac{4}{\pi}\)
(D) \(\frac{8}{\pi}\)
(E) \(\frac{16}{\pi}\)
(A) \(8\)
(B) \(16\)
(C) \(\frac{4}{\pi}\)
(D) \(\frac{8}{\pi}\)
(E) \(\frac{16}{\pi}\)
Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is
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10 Apr 2020, 16:18
10 Apr 2020, 16:18
1
Expert Reply
Volume of Milk \(= (1/2)*(4*2*8) = 32\) cubic inches
Volume of Cylinder \(= πr^2h = π*2^2*h\)
Now, \(= πr^2h = π*2^2*h = 32\)
i.e. \(h = 8/π\)
Answer:: Option D
Volume of Cylinder \(= πr^2h = π*2^2*h\)
Now, \(= πr^2h = π*2^2*h = 32\)
i.e. \(h = 8/π\)
Answer:: Option D
Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is
[#permalink]
12 May 2020, 21:15
12 May 2020, 21:15
1
If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured into a right circular cylindrical glass with radius 2 inches, how many inches high will the soymilk reach? (Assume that the capacity of the glass is greater than the volume of the soymilk.)
Equate half-the-volume of the rectangular box to the Volume of the cylinder
(l.b.h)/2 = Pi.r.r.h
(4 X 2 X 8)/2 = Pi.2.2.h
(2 X 8)/2 = Pi.h
8 = Pi.h
h = 8/Pi
Answer is Choice D.
Equate half-the-volume of the rectangular box to the Volume of the cylinder
(l.b.h)/2 = Pi.r.r.h
(4 X 2 X 8)/2 = Pi.2.2.h
(2 X 8)/2 = Pi.h
8 = Pi.h
h = 8/Pi
Answer is Choice D.
