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Re: If points A and B are randomly placed on the circumference o [#permalink]
Sir, If you solved this problem in another way it will be easy for me to absorve it.
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Re: If points A and B are randomly placed on the circumference o [#permalink]
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Hi Mithun

I do not think to solve such problem with algebra (which is the alternative method) rather than visualization will be easier :(
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Re: If points A and B are randomly placed on the circumference o [#permalink]
Hey how can we take the ratio of upper limits to find the probability ?

Originally posted by skythelimit on 06 Apr 2020, 20:10.
Last edited by skythelimit on 07 Apr 2020, 12:58, edited 1 time in total.
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Re: If points A and B are randomly placed on the circumference o [#permalink]
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skythelimit wrote:
Hey how can me take the ratio of upper limits to find the probability ?


Can you please elaborate?
I'm not how that strategy will help. It's certainly beyond the scope of the GRE.
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Re: If points A and B are randomly placed on the circumference o [#permalink]
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My approach.

calculating the circumference: 4π

Following this I try to determine in how many pieces I would need to "slice up" to get the equivalent 2 cm chords to 4π.

following this I go 4π/x =2-->yielding back 6,28-->rounding it up I assume it is 6, since 4π/6 =2,0933-->meaning I would need 6 pieces

Now since we know that it is random where the two fall, we can make our own starting point of some sort.

Following upon this I imagine we have point 0. Looking counterclockwise and clockwise we get the 2cm chord distance twice.

Since we know that we have "two pieces" out of the 6 that yield back 2cm-->we divide 2/6 =1/3 the probability that we get 2cm

Since we are looking for the opposite, the probability of not getting a chord that is less than 2cm, we have 2/3 probability

Please advise if mistaken
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Re: If points A and B are randomly placed on the circumference o [#permalink]
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Re: If points A and B are randomly placed on the circumference o [#permalink]
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