GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Given a figure of a square with a circle on it as shown
[#permalink]
Updated on: 29 Aug 2016, 01:59
Updated on: 29 Aug 2016, 01:59
1
Bookmarks
00:00
A
B
C
D
Question Stats:
70% (01:14) correct
30% (01:33) wrong based on 10 sessions
Show timer Statistics
Given a figure of a square with a circle on it as shown below and the side length of square is given as ?x?.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Answer should be D right?
Quantity A |
Quantity B |
Area of the Shaded region |
√x2/4 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Answer should be D right?
Attachments
Image52.jpg [ 4.65 KiB | Viewed 2999 times ]
Originally posted by Sonalika42 on 28 Aug 2016, 10:19.
Last edited by Carcass on 29 Aug 2016, 01:59, edited 1 time in total.
Last edited by Carcass on 29 Aug 2016, 01:59, edited 1 time in total.
Edited by Carcass
Re: Given a figure of a square with a circle on it as shown
[#permalink]
28 Aug 2016, 20:48
28 Aug 2016, 20:48
1
It seems like the top right vertex of square lies at the center of the circle so radius of circle = side length of square = x
=> Area of Circle = pi∗x2
The top and right side of the square make 90 degrees angle with each other which is 1/4th of the round circle angle of 360 degrees.
=> Area of shaded region = Area of Sector = (90/360)∗pi∗x2=(pi∗x2)/4
Since side of a square cannot be negative or zero so dividing both quantities by (x^2)/4 we get
as pi = 3.14 => Quantity A > Quantity B
=> Area of Circle = pi∗x2
The top and right side of the square make 90 degrees angle with each other which is 1/4th of the round circle angle of 360 degrees.
=> Area of shaded region = Area of Sector = (90/360)∗pi∗x2=(pi∗x2)/4
Quantity A |
Quantity B |
(pi∗x2)4 |
(x2)4 |
Since side of a square cannot be negative or zero so dividing both quantities by (x^2)/4 we get
Quantity A |
Quantity B |
pi |
1 |
as pi = 3.14 => Quantity A > Quantity B
Re: Given a figure of a square with a circle on it as shown
[#permalink]
29 Aug 2016, 06:29
29 Aug 2016, 06:29
1
@Yasir
I understand what you are saying ...my point is no where it is mentioned that one of the edge of the square is the centre of the circle....we can't make assumptions right?
This the reason why i think that answer should be D.
I understand what you are saying ...my point is no where it is mentioned that one of the edge of the square is the centre of the circle....we can't make assumptions right?
This the reason why i think that answer should be D.
