GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Mark can take three friends with him on a vacation and is
[#permalink]
30 Dec 2017, 14:09
30 Dec 2017, 14:09
Expert Reply
1
Bookmarks
00:00
Question Stats:
29% (00:59) correct
70% (01:19) wrong based on 37 sessions
Hide Show timer Statistics
Mark can take three friends with him on a vacation and is listing the possible combinations of friends. If he has five friends to choose from and is numbering each possible combination sequentially beginning with 1, which of the following numbers will appear on his list of combinations?
Indicate all possible values.
A. 2
B. 10
C. 15
D. 24
E. 60
F. 120
Indicate all possible values.
A. 2
B. 10
C. 15
D. 24
E. 60
F. 120
Drill 2
Question: 9
Page: 564
Question: 9
Page: 564
Re: Mark can take three friends with him on a vacation and is
[#permalink]
12 Jan 2018, 15:27
12 Jan 2018, 15:27
2
Expert Reply
Explanation
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
Re: Mark can take three friends with him on a vacation and is
[#permalink]
06 May 2020, 11:17
06 May 2020, 11:17
sandy wrote:
Explanation
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
what does it mean that he is listing the combinations sequentially? I get that there are a possible 10 different combinations, but I do not understand the wording of "numbering each possible combination sequentially beginning with 1". Thank you for your help!
