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m < 0 < n
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Updated on: 14 Feb 2023, 10:27
Updated on: 14 Feb 2023, 10:27
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\(m < 0 < n\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(m^{-1}\) minus \(n^{-1}\) |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Originally posted by Sonalika42 on 29 Aug 2016, 23:52.
Last edited by Carcass on 14 Feb 2023, 10:27, edited 4 times in total.
Last edited by Carcass on 14 Feb 2023, 10:27, edited 4 times in total.
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Re: m < 0 < n
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30 Aug 2016, 04:54
30 Aug 2016, 04:54
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Sonalika42 wrote:
m < 0 < n
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
m^(-1) - n^(-1) |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A: m^(-1) - n^(-1)
Quantity B: 0
NOTE: If m is NEGATIVE, then m^(-1) = 1/m = 1/NEGATIVE = NEGATIVE
If n is POSITIVE, then n^(-1) = 1/n = 1/POSITIVE = POSITIVE
So, we get:
Quantity A: NEGATIVE - POSITIVE
Quantity B: 0
Since a negative value minus a positive value will always be negative, we get:
Quantity A: NEGATIVE
Quantity B: 0
Answer:
Show: ::
B
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