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If ∠ABC = 150° and ∆CED is isosceles, what is the value of ∠
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06 May 2020, 09:47
06 May 2020, 09:47
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Question Stats:
78% (01:44) correct
21% (01:27) wrong based on 19 sessions
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If \(∠ABC = 150\)° and \(∆CED\) is isosceles, what is the value of \(∠CED\), in degrees?
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Re: If ∠ABC = 150° and ∆CED is isosceles, what is the value of ∠
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09 May 2020, 17:58
09 May 2020, 17:58
1
In quadrilateral, ABCE: sum of all angles = 360°
90° + 90° + 150° + ∠D = 360°
∠D = 30°
∆CED is isosceles, CE = CD and ∠E = ∠D = 30°
90° + 90° + 150° + ∠D = 360°
∠D = 30°
∆CED is isosceles, CE = CD and ∠E = ∠D = 30°
Re: If ∠ABC = 150° and ∆CED is isosceles, what is the value of ∠
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12 May 2020, 05:22
12 May 2020, 05:22
vndnjn wrote:
In quadrilateral, ABCE: sum of all angles = 360°
90° + 90° + 150° + ∠D = 360°
∠D = 30°
∆CED is isosceles, CE = CD and ∠E = ∠D = 30°
90° + 90° + 150° + ∠D = 360°
∠D = 30°
∆CED is isosceles, CE = CD and ∠E = ∠D = 30°
should not it be 90+90+150+ E= 360
