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Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]
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I understand what do you mean. However, when you push the first answer you think is the timer stops.

This is fine. Ideally, when you hit the first answer and then the other(s) the workbook records them.

During the real exam is the same: you elaborate the question and then you do hit your answer(s).

Substantially, it does not change. The only difference is that here the timer stops and during the real exam continues.

Nonetheless, thank you for the feedback. If you think that it is an issue write on your own to the team about the timer.

https://gre.myprepclub.com/forum/ucp.php?i ... TimerIssue

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Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]
How is choice b not wrong?
If C=3, b=6, c=9
Then, 6+3-9=0
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Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]
diegogre wrote:
How is choice b not wrong?
If C=3, b=6, c=9
Then, 6+3-9=0


The condition states that, a>b>c
a=9, b=6, c=3
9-6=3 3+3=6
6/3 =3
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Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]
As embarrasing as it sounds. I didn't realize addition and subtraction are done left to right

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Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]
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diegogre wrote:
As embarrasing as it sounds. I didn't realize addition and subtraction are done left to right

Posted from my mobile device Image


You're not the first person to believe that.
The acronym (PEMDAS or BEDMAS) seems to suggest that Addition must occur before Subtraction.

To avoid this problem, we should read the acronym as follows:
P
E
MD
AS


This format shows that multiplication and division are on the same hierarchical level. That is, neither operation is more important than the other. So, we perform these operations from left to right.
Likewise, the format shows that addition and subtraction are on the same level. So when given the option addition and subtraction, we perform those operations from left to right.
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Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]
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Addition and/or Subtraction of the multiples of a number will always yield another multiple of the number.

Therefore, A and B are correct

Now let us look at C.

The numerator abc will be a multiple of 3 and more specifically a multiple of 9 as each of these numbers contribute a 3 and 3 x 3 = 9. Thus abc is divisible by 9 and therefore by 3 as well.

Therefore C is also correct.

The correct answers are A, B, C.
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Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]
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