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GRE Math Challenge #42-Chris gave Jane x cards
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19 Sep 2014, 03:28
19 Sep 2014, 03:28
1
Expert Reply
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Question Stats:
86% (00:49) correct
13% (01:06) wrong based on 75 sessions
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Chris gave Jane x cards. He gave Betty one card more than he gave Jane & he gave Paul two cards fewer than he gave Betty.
In terms of x, how many cards did Chris give Betty, Jane & Paul altogether?
A. 3x+1
B. 3x
C. 3x-1
D. x-1
E. x/3
In terms of x, how many cards did Chris give Betty, Jane & Paul altogether?
A. 3x+1
B. 3x
C. 3x-1
D. x-1
E. x/3
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: GRE Math Challenge #42-Chris gave Jane x cards
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23 Oct 2018, 06:49
23 Oct 2018, 06:49
1
sandy wrote:
Chris gave Jane x cards. He gave Betty one card more than he gave Jane & he gave Paul two cards fewer than he gave Betty.
In terms of x, how many cards did Chris give Betty, Jane & Paul altogether?
A. 3x+1
B. 3x
C. 3x-1
D. x-1
E. x/3
In terms of x, how many cards did Chris give Betty, Jane & Paul altogether?
A. 3x+1
B. 3x
C. 3x-1
D. x-1
E. x/3
Chris gave Jane x cards.
Chris gave Betty one card more than he gave Jane
So, x + 1 = number of cards Chris gave Betty
Chris gave Paul two cards fewer than he gave Betty
So, x + 1 - 2 = number of cards Chris gave Paul
Simplify: x - 1 = number of cards Chris gave Paul
In terms of x, how many cards did Chris give Betty, Jane & Paul altogether?
TOTAL cards given = x + (x + 1) + (x - 1)
= 3x
Answer: B
Cheers,
Brent
Re: GRE Math Challenge #42-Chris gave Jane x cards
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02 Dec 2021, 10:13
02 Dec 2021, 10:13
Expert Reply
Bumping for discussion. Try this one and get Kudos for a correct solution!!!!
