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3a/a-2b=2

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3a/a-2b=2 [#permalink] New post   26 May 2020, 10:49
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\(\frac{3a}{a-2b}=2\)


Quantity A
Quantity B
\(\frac{4a-2b}{a-2b }\)
\(a+4b\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: 3a/a-2b=2 [#permalink] New post   26 May 2020, 10:50
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Re: 3a/a-2b=2 [#permalink] New post   26 May 2020, 15:33
1
given,

3a/ ( a-2b ) = 2 = 6 /3

so, 3a = 6 .... a = 2

and a - 2b = 3

2-2b= 3
-2b = 1
b= -1/2

substituting the values of a and b in the comparison we get,

A = 4a-2b / ( a-2b) = ( 4x2 - (2x -1/2) )/ 3 = ( 8 +1) / 3 = 3

and

B = a + 4b = 2 + (4 x (-1/2) ) = 2 -2 = 0

Hence A > B ( option A)
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Re: 3a/a-2b=2 [#permalink] New post   27 May 2020, 04:00
3
Given \(\frac{3a}{a-2b}=2\)

hence simplifying this 3a = 2a -4b

a = - 4b

Substituting this in Quantity A = \(\frac{-16b-2b}{-4b-2b }\) = \(\frac{-18b}{-6b}\) = 3

Substituting a = - 4b in Quantity B = -4b + 4b = 0

Hence Quantity A > Quantity B answer is A
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Re: 3a/a-2b=2 [#permalink]
27 May 2020, 04:00
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