Carcass wrote:
What is the smallest integer n for which \(25^n > 5^{12}\) ?
We have: 25^n > 5^12
To rewrite this inequality with the SAME base, we'll replace 25 with
5².
When we do so, we get: (
5²)^n > 5^12
Apply the Power of a Power law to get:
5^(2n) > 5^12This means that it must be the case that 2n > 12
Divide both sides of the inequality by 2 to get: n > 6
What is the smallest integer n for which 25^n > 5^12 ?We now know that n > 6
So, 7 is the smallest possible INTEGER value that satisfies this inequality.
Answer: 7
Cheers,
Brent