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If the sum of two positive integers is 24 and the difference
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29 May 2020, 11:09
29 May 2020, 11:09
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Question Stats:
95% (01:31) correct
4% (04:21) wrong based on 24 sessions
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If the sum of two positive integers is 24 and the difference of their squares is 48, what is the product of the two integers?
(A) 108
(B) 119
(C) 128
(D) 135
(E) 143
(A) 108
(B) 119
(C) 128
(D) 135
(E) 143
Re: If the sum of two positive integers is 24 and the difference
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29 May 2020, 11:09
29 May 2020, 11:09
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
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Re: If the sum of two positive integers is 24 and the difference
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29 May 2020, 11:16
29 May 2020, 11:16
1
Carcass wrote:
If the sum of two positive integers is 24 and the difference of their squares is 48, what is the product of the two integers?
(A) 108
(B) 119
(C) 128
(D) 135
(E) 143
(A) 108
(B) 119
(C) 128
(D) 135
(E) 143
Let the values = x and y
The sum of two positive integers is 24
So, x + y = 24
The difference of their squares is 48
So, x² - y² = 48
Factor to get: (x + y)(x - y) = 48
Replace to get: (24)(x - y) = 48
So, (x - y) = 2
We now have:
x + y = 24
x - y = 2
Add these equations to get: 2x = 26, which means x = 13
If x = 13, then y = 11
So, xy = (13)(11) = 143 = E
Cheers,
Brent
