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If X is the hundredths digit in the decimal 0.1X and if Y is
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31 May 2020, 09:57
31 May 2020, 09:57
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54% (01:15) wrong based on 83 sessions
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If X is the hundredths digit in the decimal 0.1X and if Y is the thousandths digit in the decimal 0.02Y ,where X and Y are nonzero digits,which of the following is closest to the greatest possible value of \(\frac{0.1X}{0.02Y}\) ?
A. 4
B. 5
C. 6
D. 9
E. 10
A. 4
B. 5
C. 6
D. 9
E. 10
Re: If X is the hundredths digit in the decimal 0.1X and if Y is
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31 May 2020, 09:58
31 May 2020, 09:58
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
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Re: If X is the hundredths digit in the decimal 0.1X and if Y is
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31 May 2020, 15:24
31 May 2020, 15:24
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Carcass wrote:
If X is the hundredths digit in the decimal 0.1X and if Y is the thousandths digit in the decimal 0.02Y ,where X and Y are nonzero digits,which of the following is closest to the greatest possible value of \(\frac{0.1X}{0.02Y}\) ?
A. 4
B. 5
C. 6
D. 9
E. 10
A. 4
B. 5
C. 6
D. 9
E. 10
To MAXIMIZE the value of 0.1X/0.02Y, we must MAXIMIZE the numerator (0.1X) and MINIMIZE the denominator (0.02Y)
So, the numerator is maximized when X = 9. So, the numerator is 0.19
The denominator is minimized when Y = 1. So, the denominator is 0.021
So, we must determine the value of 0.19/0.021
IMPORTANT: We need not calculate the value of 0.19/0.021
Instead, just recognize that 0.19/0.02 = 9.5, which is halfway between 9 and 10
Since 0.021 is a bit bigger than 0.02, we know that 0.19/0.021 is a bit LESS THAN 9.5
So, 0.19/0.021 must be closest to 9
Answer: D
Cheers,
Brent
