Attachment:
#greprepclub Within rectangle ACDF, both ABGH and BCDE are squares.jpg [ 11 KiB | Viewed 2666 times ]
The figure looks like above
Now , in this question is just to follow the wire until the solution. It is just a consequence or chain
We do know that ACDF is a rectangle so the side AC > CD
We do know that square ABGH have all sides =
we do know that 3x>y>2x
Suppose x= 2 then y =5
From this All sides of ABGH are 2
The parallel side CD is 2+5=7
because ACDF is a rectangle side AF =2+5=7 and CD as well =7
Moreover, we have a rectangle so the side AC must be AT LEAST 8 because it is longer than side CD which is 7
So AC is 8 and because AB is 2, the side portion labeled Z must be 6
The area or the entire rectangle is 8*7=56
HGEF must be also a rectangle because we do know that x = 2 BUT y=5
The area is 2*5=10
So the ratio ACDF to HGEF is = 56/10 and this must be greater than 5
The answer is A