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Three consecutive even integers have a sum of 102. If x repr
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24 Mar 2020, 06:33
24 Mar 2020, 06:33
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Three consecutive even integers have a sum of 102. If x represents the least number in the set, what equation can be used to determine the value of the sum of the integers?
A. x + (x + 1) + (x + 2) = 102
B. x + (x + 1) + (x + 3) = 102
C. x + (x + 2) + (x + 4) = 102
D. x + 2x + 4x = 102
E. x + x + x = 102
Kudos for the right answer and explanation
A. x + (x + 1) + (x + 2) = 102
B. x + (x + 1) + (x + 3) = 102
C. x + (x + 2) + (x + 4) = 102
D. x + 2x + 4x = 102
E. x + x + x = 102
Kudos for the right answer and explanation
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Re: Three consecutive even integers have a sum of 102. If x repr
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07 Jun 2020, 01:59
07 Jun 2020, 01:59
1
We have sum of three consecutive integers as 102 and the least integer as x
Now we know that we have alternate odd and even numbers
So, if x is even then next number x+1 will be odd and x+2 will become even
and next number x+3 is odd and x+4 will be even
=> Three consecutive even numbers will be x, x+2 and x+4
So, sum of three consecutive even numbers will be x + (x+2) + (x+4) = 102
So, answer will be C
Hope it helps!
Now we know that we have alternate odd and even numbers
So, if x is even then next number x+1 will be odd and x+2 will become even
and next number x+3 is odd and x+4 will be even
=> Three consecutive even numbers will be x, x+2 and x+4
So, sum of three consecutive even numbers will be x + (x+2) + (x+4) = 102
So, answer will be C
Hope it helps!
gmatclubot
Re: Three consecutive even integers have a sum of 102. If x repr [#permalink]
07 Jun 2020, 01:59
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