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Re: n is a positive integer. The remainder when 5n is divided by [#permalink]
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You could just write out \(\frac{5n}{4}\) and then write out values using different values of n, until you found a remainder of 3. Then you could use that value of n to find A, and then compare it to B. Ex. if n = 3 then you have 15/4 which is equal to 3 with a remainder of 3 (mixed fraction of 3 and 3/4 expresses this). Then plug in 3 for 10n/4 in the second part and you get 30/4 = 7 R2 (same idea is expressed by mixed fraction 7 2/4). So, based on that the answer is C.

One might ask, is this always true? What about other values of n with a R2? It happens to be true, but my method doesn't show it. Brent's did. The method I used gives a reasonable guess, I think, of the right answer.

Originally posted by arc601 on 15 Sep 2019, 13:43.
Last edited by arc601 on 09 Jun 2020, 21:06, edited 2 times in total.
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Re: n is a positive integer. The remainder when 5n is divided by [#permalink]
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Re: n is a positive integer. The remainder when 5n is divided by [#permalink]
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5n = mult(4) + 3; 3 is the remainder

10 n = 5n * 2 = [mult(4) + 3] * 2 = mult(4) + 6 = mult(4) + 2

So, the remainder is always 2.
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n is a positive integer. The remainder when 5n is divided by [#permalink]
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The remainder when 5n is divided by 4 is 3

Theory: Dividend = Divisor*Quotient + Remainder

5n -> Dividend
4 -> Divisor
a -> Quotient (Assume)
3 -> Remainders
=> 5n = 4*a + 3 = 4a + 3

Quantity A: The remainder when 10n is divided by 4

10n = 2*5n = 2*(4a + 3) = 8a + 6 = 4*2a + 4 + 2 = 4*(2a + 1) + 2
=> 10n when divided by 4 gives 2a + 1 as quotient and 2 as remainder

Clearly, Quantity A(2) = Quantity B(2)

So, Answer will be C
Hope it helps!

Watch the following video to learn the Basics of Remainders

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Re: n is a positive integer. The remainder when 5n is divided by [#permalink]
GreenlightTestPrep wrote:
sandy wrote:
n is a positive integer.
The remainder when 5n is divided by 4 is 3.

Quantity A
Quantity B
The remainder when 10n is divided by 4
2


There's a nice rule that say, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3


The remainder when 5n is divided by 4 is 3
Applying the above rule, we get: 5n = 4k + 3 (for some integer k)
Divide both sides by 5 to get: n = (4k + 3)/5

Quantity A: The remainder when 10n is divided by 4
Replace n with (4k + 3)/5 to get: 10n = 10((4k + 3)/5) = 8k + 6
If 10n = 8k + 6, what is the remainder when 8k + 6 is divided by 4?
Notice that 8k + 6 = 8k + 4 + 2
= 4(2k + 1) + 2
As we can see, 4(2k + 1) is a MULTIPLE OF 4
This means that 4(2k + 1) + 2 is 2 greater than a MULTIPLE OF 4
So, if we divide 4(2k + 1) + 2 by 4, the remainder will be 2
We get....
Quantity A: 2
Quantity B: 2

Answer:
Show: ::
C


RELATED VIDEO


Hi Brent GreenlightTestPrep
In this type of remainder question, to clarify does it mean we should never add/combine any numbers as in below line?

"This means that 4(2k + 1) + 2 is 2 greater than a MULTIPLE OF 4"

As I have add 2 + 1 = 3 ( Remainder). Therefore A > B.
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Re: n is a positive integer. The remainder when 5n is divided by [#permalink]
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Re: n is a positive integer. The remainder when 5n is divided by [#permalink]
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