Carcass wrote:
If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131
(B) 135
(C) 139
(D) 147
(E) 188
Let
x = Jake's present weight in pounds
So,
x - 8 = Jake's hypothetical weight IF he were to lose 8 pounds
If Jake loses 8 pounds, he will weigh twice as much as his sister. In other words, the sister weighs HALF as much as Jake's hypothetical weight of x - 8 pounds
So,
(x - 8)/2 = sister's present weight
Together they NOW weigh 278 pounds. So, Jake's present weight + sister's present weight = 278
So,
x +
(x - 8)/2 = 278
Eliminate the fraction by multiplying both sides by 2 to get: 2x + (x - 8) = 556
Simplify: 3x - 8 = 556
Add 8 to both sides: 3x = 564
Solve: x = 564/3 = 188
Answer: E
Cheers,
Brent