Farina wrote:
The area of isosceles right triangle XYZ equals 9. Which of the following could be the perimeter?
I. 12
II. 13 + √145
III. 6√2 + 6
(A) I only
(B) I and III
(C) III only
(D) I and II
(E) All of the above
Here's what an isosceles right triangle looks like:
![Image](https://i.imgur.com/mWJlVsC.png)
Given: The area = 9
Area of triangle = (base)(height)/2So we can write: (x)(x)/2 = 9
Multiply both sides of the equation by 2 to get: x² = 18
Solve: x = √18
Simplify: x = 3√2
So our triangle looks like this:
Aside: If x = 3√2, then (√2)(x) = (√2)(3√2) = 6Perimeter = 3√2 + 3√2 + 6 = 6√2 + 6
Answer: C
Cheers,
Brent