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Let d be defined as d^2/2 for all values
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30 Jun 2020, 09:08
30 Jun 2020, 09:08
Expert Reply
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Question Stats:
65% (00:28) correct
34% (00:47) wrong based on 70 sessions
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Let \(d \triangle\) be defined as \(\frac{d^2}{2}\) for all values of d.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\([d \triangle] \triangle\) |
\(\frac{d^4}{8}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: Let d be defined as d^2/2 for all values
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30 Jun 2020, 09:09
30 Jun 2020, 09:09
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
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Re: Let d be defined as d^2/2 for all values
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30 Jun 2020, 09:55
30 Jun 2020, 09:55
1
Carcass wrote:
Let \(d \triangle\) be defined as \(\frac{d^2}{2}\) for all values of d.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\([d \triangle] \triangle\) |
\(\frac{d^4}{8}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
QUANTITY A: \([d \triangle] \triangle\)
\([d \triangle] = \frac{d^2}{2}\)
So, \([d \triangle] \triangle = \frac{d^2}{2}\triangle = \frac{(\frac{d^2}{2})^2}{2} = \frac{\frac{d^4}{4}}{2}=(\frac{d^4}{4})(\frac{1}{2}) = \frac{d^4}{8}\)
QUANTITY B: \(\frac{d^4}{8}\)
Answer: C
Cheers,
Brent
