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If the radius of the circle above is 3 and point 0 is the ce

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If the radius of the circle above is 3 and point 0 is the ce [#permalink] New post   31 May 2020, 09:49
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If the radius of the circle above is 3 and point 0 is the center of the circle, what is the area of triangle ABC?


A. \(4 \sqrt{3}\)

B. \(6 \sqrt{2}\)

C. \(6 \sqrt{3}\)

D. \(12 \sqrt{2}\)

E. \(18 \sqrt{3}\)
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Re: If the radius of the circle above is 3 and point 0 is the ce [#permalink] New post   31 May 2020, 09:49
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Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
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Re: If the radius of the circle above is 3 and point 0 is the ce [#permalink] New post   Updated on: 12 Jul 2020, 22:15
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AC is the diameter of the circle and it must be 6.
Triangle ABC is 30-60-90 and thus, BC = 6 / √3.
Area of triangle = 1/2 * 6 * 6 / √3.
we get 18 / √3
6 * √3 * √3 / √3
Thus, 6*√3

Originally posted by sukrut96 on 31 May 2020, 21:43.
Last edited by sukrut96 on 12 Jul 2020, 22:15, edited 1 time in total.
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Re: If the radius of the circle above is 3 and point 0 is the ce [#permalink] New post   12 Jul 2020, 16:48
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sukrut96 wrote:
AC is the radius of the circle and it must be 6.
Triangle ABC is 30-60-90 and thus, BC = 6 / √3.
Area of triangle = 1/2 * 6 * 6 / √3.
we get 18 / √3
6 * √3 * √3 / √3
Thus, 6*√3


one correction: Diameter is 6 not radius
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Re: If the radius of the circle above is 3 and point 0 is the ce [#permalink] New post   12 Jul 2020, 22:16
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Farina wrote:
sukrut96 wrote:
AC is the radius of the circle and it must be 6.
Triangle ABC is 30-60-90 and thus, BC = 6 / √3.
Area of triangle = 1/2 * 6 * 6 / √3.
we get 18 / √3
6 * √3 * √3 / √3
Thus, 6*√3


one correction: Diameter is 6 not radius


Yes, you're right. Thanks for correcting me :)
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sammyG
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Re: If the radius of the circle above is 3 and point 0 is the ce [#permalink] New post   01 Aug 2020, 10:48
How do you know which angle is 30 and which one is 60?
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Re: If the radius of the circle above is 3 and point 0 is the ce [#permalink]
01 Aug 2020, 10:48
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