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If the radius of the circle above is 3 and point 0 is the ce
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31 May 2020, 09:49
31 May 2020, 09:49
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68% (02:30) correct
31% (01:49) wrong based on 57 sessions
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#greprepclub If the radius of the circle above is 3 and point 0 is the center of the circle, what is the area of triangle ABC .jpg [ 18.68 KiB | Viewed 2307 times ]
If the radius of the circle above is 3 and point 0 is the center of the circle, what is the area of triangle ABC?
A. \(4 \sqrt{3}\)
B. \(6 \sqrt{2}\)
C. \(6 \sqrt{3}\)
D. \(12 \sqrt{2}\)
E. \(18 \sqrt{3}\)
Re: If the radius of the circle above is 3 and point 0 is the ce
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31 May 2020, 09:49
31 May 2020, 09:49
1
Expert Reply
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: If the radius of the circle above is 3 and point 0 is the ce
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Updated on: 12 Jul 2020, 22:15
Updated on: 12 Jul 2020, 22:15
2
AC is the diameter of the circle and it must be 6.
Triangle ABC is 30-60-90 and thus, BC = 6 / √3.
Area of triangle = 1/2 * 6 * 6 / √3.
we get 18 / √3
6 * √3 * √3 / √3
Thus, 6*√3
Triangle ABC is 30-60-90 and thus, BC = 6 / √3.
Area of triangle = 1/2 * 6 * 6 / √3.
we get 18 / √3
6 * √3 * √3 / √3
Thus, 6*√3
