For simplifying the solution lets assume the price of the home in 1992 is 100
From 1992 to 1993, the price of a home increased by x %
=> Price in 1993 = Price in 1992 + x% of Price of 1992 = 100 + x% of 100 = 100 + \(\frac{x}{100}\) * 100 = 100 + x

From 1993 to 1994, the price of the home then decreased by x %
=> price in 1994 = Price in 1993 - x% of price in 1993 = Price in 1993 * (1 - x%) = (100 + x) * (1 - \(\frac{x}{100}\))
=> Price in 1994 = (100 + x) * (\(\frac{100 - x}{100}\))
[ Using (a+b) * (a-b) = \(a^2\) - \(b^2\), we have]
=> Price in 1994 = \(\frac{(100^2 - x^2)}{ 100}\) = 100 - \(\frac{x^2}{100}\)
Now, we know that x is a positive number => \(\frac{x^2}{100}\) > 0
=> Price in 1994 < 100
=> Price in 1992 (which is 100) > Price in 1994
=> Quantity A > Quantity B

So, answer will be A
Hope it helps!