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f(x)=x^2+2x-2
[#permalink]
20 Jul 2020, 11:29
20 Jul 2020, 11:29
Expert Reply
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Question Stats:
74% (00:55) correct
24% (00:40) wrong based on 28 sessions
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\(f(x)=x^2+2x-2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The value of x when \(f(x)=13\) |
3 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: f(x)=x^2+2x-2
[#permalink]
23 Jul 2020, 07:09
23 Jul 2020, 07:09
1
Carcass wrote:
\(f(x)=x^2+2x-2\)
Quantity A |
Quantity B |
The value of x when \(f(x)=13\) |
3 |
If \(f(x) = 13\), then we can write: \(x^2+2x-2 = 13\)
To solve this equation, let's first subtract \(13\) from both sides of the equation to get: \(x^2+2x-15 = 0\)
Factor to get: \((x-3)(x+5) = 0\)
When we solve we get EITHER \(x = 3\) OR \(x = -5\)
If \(x = 3\), then the two quantities are equal
If \(x = -5\), then Quantity B is greater
Answer: D
Cheers,
Brent
gmatclubot
Re: f(x)=x^2+2x-2 [#permalink]
23 Jul 2020, 07:09
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