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3x² + 5y² > 200
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22 Jul 2020, 02:13
22 Jul 2020, 02:13
Expert Reply
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Question Stats:
58% (01:33) correct
41% (01:15) wrong based on 58 sessions
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\(3x² + 5y² > 200\)
\(x² + y² = 61\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(x² + y² = 61\)
Quantity A |
Quantity B |
y |
3 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: 3x² + 5y² > 200
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22 Jul 2020, 02:14
22 Jul 2020, 02:14
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more GRE Quant Theory and Practice, see
GRE Prep Club - MATH Book for the GRE Exam
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more GRE Quant Theory and Practice, see
GRE Prep Club - MATH Book for the GRE Exam
Re: 3x² + 5y² > 200
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22 Jul 2020, 11:32
22 Jul 2020, 11:32
2
Step 1: Manipulating the given equation
\(x^2 + y^2\) = 61
\(x^2 = 61 - y^2\)
Step 2: Simplifying
Using value of \(y^2\) in the given inequality
3*(61 - \(y^2\)) + 5\(y^2\) > 200
183 + 2\(y^2\) > 200
\(y^2 \)> 17/2
\(y^2\) > 8.5
Taking square root on both the sides
y > 2.9 (approx)
Hence the relation cannot be determined
D is correct
\(x^2 + y^2\) = 61
\(x^2 = 61 - y^2\)
Step 2: Simplifying
Using value of \(y^2\) in the given inequality
3*(61 - \(y^2\)) + 5\(y^2\) > 200
183 + 2\(y^2\) > 200
\(y^2 \)> 17/2
\(y^2\) > 8.5
Taking square root on both the sides
y > 2.9 (approx)
Hence the relation cannot be determined
D is correct
