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(1/8-3/10)+(1/4-1/5)+(5/8-1/2)=
[#permalink]
20 Jul 2020, 11:41
20 Jul 2020, 11:41
Expert Reply
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Question Stats:
57% (00:41) correct
42% (02:26) wrong based on 7 sessions
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Joined: 10 Apr 2015
Posts: 6218
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Re: (1/8-3/10)+(1/4-1/5)+(5/8-1/2)=
[#permalink]
23 Jul 2020, 08:04
23 Jul 2020, 08:04
Carcass wrote:
Given: \((\frac{1}{8}-\frac{3}{10})+(\frac{1}{4}-\frac{1}{5})+(\frac{5}{8}-\frac{1}{2})\)
Rewrite with \(40 \) as common denominator: \((\frac{5}{40}-\frac{12}{40})+(\frac{10}{40}-\frac{8}{40})+(\frac{25}{40}-\frac{20}{40})\)
Simplify the parts in brackets: \((\frac{-7}{40})+(\frac{2}{40})+(\frac{5}{40})\)
Evaluate: \(\frac{0}{40}= 0\)
Answer: 0
Re: (1/8-3/10)+(1/4-1/5)+(5/8-1/2)=
[#permalink]
23 Jul 2020, 10:55
23 Jul 2020, 10:55
1
Carcass wrote:
Step 1: Rearranging the terms
\((\frac{1}{8} + \frac{1}{4} + \frac{5}{8}) - (\frac{3}{10} + \frac{1}{5} + \frac{1}{2})\)
Step 2: Calculation
\((\frac{1}{8} + \frac{2}{8} +\frac{ 5}{8}) - (\frac{3}{10} + \frac{2}{10} + \frac{5}{10})\)
= \((\frac{8}{8}) - (\frac{10}{10})\)
= 1 -1
= 0
