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The function f is defined by f(x)=2^x-3. If f(x)=31, then th
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24 Jul 2020, 07:10
24 Jul 2020, 07:10
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The function f is defined by \(f(x)=2^x-3\). If \(f(x)=31\), then the value of x is between?
A) 1 and 2
B) 2 and 3
C) 3 and 4
D) 4 and 5
E) 5 and 6
A) 1 and 2
B) 2 and 3
C) 3 and 4
D) 4 and 5
E) 5 and 6
Re: The function f is defined by f(x)=2^x-3. If f(x)=31, then th
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24 Jul 2020, 07:11
24 Jul 2020, 07:11
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Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more GRE Quant Theory and Practice, see
GRE Prep Club - MATH Book for the GRE Exam
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more GRE Quant Theory and Practice, see
GRE Prep Club - MATH Book for the GRE Exam
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Re: The function f is defined by f(x)=2^x-3. If f(x)=31, then th
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24 Jul 2020, 07:35
24 Jul 2020, 07:35
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Carcass wrote:
The function f is defined by \(f(x)=2^x-3\). If \(f(x)=31\), then the value of x is between?
A) 1 and 2
B) 2 and 3
C) 3 and 4
D) 4 and 5
E) 5 and 6
A) 1 and 2
B) 2 and 3
C) 3 and 4
D) 4 and 5
E) 5 and 6
Given: f(x) = 2^x - 3
So, if f(x) = 31, we can write: 2^x - 3 = 31
Add 3 to both sides to get: 2^x = 34 [solve this equation for x]
We know that 2^5 = 32
and 2^6 = 64
Since 34 lies between 32 and 64, we can conclude that x is between 5 and 6
Answer: E
