GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The inverted cone pictured below is initially filled to heig
[#permalink]
13 May 2020, 10:35
13 May 2020, 10:35
Expert Reply
7
Bookmarks
00:00
Question Stats:
50% (02:05) correct
49% (02:02) wrong based on 150 sessions
Hide Show timer Statistics
The inverted cone pictured below is initially filled to height \(h_0\) with a volume of \(1,000 \pi\) water. 60 percent of the water is drained from the cone and the water level falls to height \(h_1\). For a cone with radius r and height h, volume =
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
#greprepclub The inverted cone pictured below is initially filled.jpg [ 29.65 KiB | Viewed 6911 times ]
Quantity A |
Quantity B |
\(\frac{h_1}{h_0}\) |
\(0.4\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Show: ::
Attachment:
#greprepclub The inverted cone pictured below is initially filled.jpg [ 29.65 KiB | Viewed 6911 times ]
Re: The inverted cone pictured below is initially filled to heig
[#permalink]
13 May 2020, 11:26
13 May 2020, 11:26
3
2
Bookmarks
Attachment:
Mpz51ex.png [ 19.92 KiB | Viewed 5484 times ]
Lets assume,
when the cone is filled till h0, the radius of circular cross section of cone till that height = r0 (which is AB)
when the cone is filled till h1, the radius of circular cross section of cone till that height = r1 (which is CD)
From, similarity of triangels,
AB/CD = OA/OC
=> r0/r1 = h0/h1 ........... (1)
Now,
60% of water was drained
=> initial volume / final volume = 100 / 40
=> [ (1/3) * pi * r0 * r0 * h0] / [ (1/3) * pi * r1 * r1 * h1] = 1 / 0.4
from (1) we can replace the value of r0/r1
=> (h0*h0*h0)/(h1*h1*h1) = 1/0.4
=> h1/h0 = cube root of 0.4 = 0.7368 > 0.4
So, the answer is A.
General Discussion
Re: The inverted cone pictured below is initially filled to heig
[#permalink]
13 May 2020, 10:36
13 May 2020, 10:36
1
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
