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When the positive integer x is divided by 6, the remainder i
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12 Aug 2018, 15:35
12 Aug 2018, 15:35
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46% (01:25) correct
53% (01:36) wrong based on 79 sessions
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When the positive integer x is divided by 6, the remainder is 4. Each of the following could also be an integer EXCEPT
(A) \(\frac{x}{2}\)
(B) \(\frac{x}{3}\)
(C) \(\frac{x}{7}\)
(D) \(\frac{x}{11}\)
(E) \(\frac{x}{17}\)
(A) \(\frac{x}{2}\)
(B) \(\frac{x}{3}\)
(C) \(\frac{x}{7}\)
(D) \(\frac{x}{11}\)
(E) \(\frac{x}{17}\)
Re: When the positive integer x is divided by 6, the remainder i
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15 Aug 2018, 05:24
15 Aug 2018, 05:24
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Explanation
When dealing with remainder questions on the GRE, the best thing to do is test a few real numbers:
Multiples of 6 are 0, 6, 12, 18, 24, 30, 36, etc.
Numbers with a remainder of 4 when divided by 6 are those 4 greater than the multiples of 6:
x could be 4, 10, 16, 22, 28, 34, 40, etc.
You could keep listing numbers, but this is probably enough to establish a pattern.
(A) \(\frac{x}{2}\) → ALL of the listed x values are divisible by 2. Eliminate (A).
(B) \(\frac{x}{3}\) → NONE of the listed x values are divisible by 3, but continue checking.
(C) \(\frac{x}{7}\) → 28 is divisible by 7.
(D) \(\frac{x}{11}\) → 22 is divisible by 11.
(E) \(\frac{x}{18}\) → 34 is divisible by 17.
The question is “Each of the following could also be an integer EXCEPT.” Since four of the choices could be integers, (B) must be the answer.
When dealing with remainder questions on the GRE, the best thing to do is test a few real numbers:
Multiples of 6 are 0, 6, 12, 18, 24, 30, 36, etc.
Numbers with a remainder of 4 when divided by 6 are those 4 greater than the multiples of 6:
x could be 4, 10, 16, 22, 28, 34, 40, etc.
You could keep listing numbers, but this is probably enough to establish a pattern.
(A) \(\frac{x}{2}\) → ALL of the listed x values are divisible by 2. Eliminate (A).
(B) \(\frac{x}{3}\) → NONE of the listed x values are divisible by 3, but continue checking.
(C) \(\frac{x}{7}\) → 28 is divisible by 7.
(D) \(\frac{x}{11}\) → 22 is divisible by 11.
(E) \(\frac{x}{18}\) → 34 is divisible by 17.
The question is “Each of the following could also be an integer EXCEPT.” Since four of the choices could be integers, (B) must be the answer.
Re: When the positive integer x is divided by 6, the remainder i
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27 Jul 2020, 10:30
27 Jul 2020, 10:30
I was confused here with the question, x should be the same number in the question and divisible by " All" the choices except the answer. What was the clue of concluding Sandy answer?
